f(x)=(x+4)(2x^1-1)

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Solution for f(x)=(x+4)(2x^1-1) equation:


Simplifying
f(x) = (x + 4)(2x + -1)

Multiply f * x
fx = (x + 4)(2x + -1)

Reorder the terms:
fx = (4 + x)(2x + -1)

Reorder the terms:
fx = (4 + x)(-1 + 2x)

Multiply (4 + x) * (-1 + 2x)
fx = (4(-1 + 2x) + x(-1 + 2x))
fx = ((-1 * 4 + 2x * 4) + x(-1 + 2x))
fx = ((-4 + 8x) + x(-1 + 2x))
fx = (-4 + 8x + (-1 * x + 2x * x))
fx = (-4 + 8x + (-1x + 2x2))

Combine like terms: 8x + -1x = 7x
fx = (-4 + 7x + 2x2)

Solving
fx = -4 + 7x + 2x2

Solving for variable 'f'.

Move all terms containing f to the left, all other terms to the right.

Divide each side by 'x'.
f = -4x-1 + 7 + 2x

Simplifying
f = -4x-1 + 7 + 2x

Reorder the terms:
f = 7 + -4x-1 + 2x

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